<< Hide Menu

📚

 > 

♾️ 

 > 

👑

1.9 Connecting Multiple Representations of Limits

6 min readjune 18, 2024

1.9 Connecting Multiple Representations of Limits

Throughout this unit, we’ve learned how to determine (or estimate) limits from different kinds of representations, including graphs, tables, and algebraic expressions. In this topic, we’ll practice connecting these various representations.


📈Connecting Multiple Representations of Limits

To connect the numerical, graphical, and algebraic representations of limits, we have to be able to gain information from each representation individually and then figure out how the information corresponds or corroborates with each other. This will allow us to gain a more complete understanding of the behavior of the function as x approaches the limit.

For example, we can use the numerical representation to approximate the limit, and then confirm our answer by observing the graphical representation and/or determining the exact limit using the algebraic representation. Or vice versa! 🔂

An important point to note is that sometimes one representation may be more informative than the others. For example, a function that is difficult to manipulate algebraically can be graphed to understand the behavior of the function as x approaches the limit.

Here’s a quick review of each of these:

  1. 🔢 Numerical Representation - This is the most common method used to determine limits and involves plugging in different values of x that are close to the limit and seeing what the approaches. This data is presented in a table and gives us an approximation of the limit, not the exact solution.
  2. 📊 Graphical Representation - This method involves and observing the behavior of the as x approaches the limit. This method is also not an exact solution.
  3. 📝 Algebraic Representation - This involves using algebraic manipulation to determine the exact solution for the limit. With this, you may factor, rationalize denominators, or work with trig!

Now let’s give a question a try!

✏️ Multiple Representations of Limits: Walkthrough

Let ff be a function where limx0f(x)=1\lim_{x \to 0}f(x) = 1. Which of the following could represent ff?

Option A)

Untitled

Image Courtesy of Desmos

Note: The graph has a removable discontinuity at (0,1)(0, 1). We’ll talk about this more in the next key topic.

Option B)

xx-0.2-0.1-0.0010.0010.10.2
f(x)f(x)1.041.011.0000011.0000011.011.04

Option C)

f(x)={x5,x<01,x 0f(x)=\begin{cases} x-5, x<0\\ 1, x\geq 0\end{cases}

How can we tackle this problem? Well, we can look through the different options and evaluate the limx0f(x)\lim_{x \to 0}f(x) for each one and see if it equals 11. You essentially want to act like each option is on its own so you don’t get distracted by the others! 👀

📈 First, let’s take a look at the graph in a). We see that f(x)f(x) approaches 11 as xx approaches 00 from the left, but f(x)f(x) approaches 3-3 and as xx approaches 00 from the right. Therefore, a) is not the correct answer.

🔢 Next, if we look at the table in b), we see that as the values of xx approach 00 on both the left and right sides, the values of f(x)f(x) approach 11, so the function depicted in b) could represent limx0f(x)=1\lim_{x \to 0}f(x) = 1.

🤔 To confirm that b) is the correct answer, we can look at the function given in c). For xx values approaching 00 on the left we see that f(x)f(x) approaches 050-5 or 5-5, and for xx values approaching 00 on the right we see that f(x)f(x) is 11. Since only one side approaches 11, limx0f(x)\lim_{x \to 0}f(x) is not equal to 11.

Therefore, b) is the correct answer.


📝 Limits Practice Problem

Now it’s time for you to do some practice on your own! 🔍

❓Limits Practice Question

Let ff be a function where limx4f(x)=5\lim_{x \to 4}f(x) = 5. Which of the following could represent ff?

a)

f(x)={x23x4x4,x46,x=4f(x)=\begin{cases} \frac{x^2-3x-4}{x-4}, x \neq 4\\ 6, x = 4\end{cases}

b)

Untitled

Image Courtesy of Desmos

c)

xx3.83.93.99944.0014.014.02
f(x)f(x)6.26.016.00144.9994.94.8

✅ Limits Practice Solution

To solve this problem we can look through the answer choices and evaluate the limx4f(x)\lim_{x \to 4}f(x) for each one and see if it equals 55.

First, if we look at the equation in a), we see that we can algebraically manipulate it to be

f(x)={(x+1)(x4)x4,x46,x=4f(x)=\begin{cases} \frac{(x+1)(x-4)}{x-4}, x \neq 4\\ 6, x = 4\end{cases}

Since we’re interested in the behavior of the function as xx approaches 4, we only care about the part of the function where x4x \neq 4.

(x+1)(x4)x4=x+1\frac{(x+1)(x-4)}{x-4}=x+1

Plugging x=4x=4 in gets us 55, so a) is the correct answer.

To confirm that a) is the correct answer, we can look at both the graph in b) and the table in c).

We see that while the graph in b) depicts f(x)f(x) approaching 55 as xx approaches 44 from the left, f(x)f(x) approaches 66 and not 55 as xx approaches 44 from the right. Therefore, b) is not the correct answer.

From the table in c), we see that for xx values approaching 44 on the left, f(x)f(x) approaches 66, and for xx values approaching 44 on the right, f(x)f(x) approaches 55. Since only one side approaches 55, limx4f(x)\lim_{x \to 4}f(x) is not equal to 55.

Therefore, a) is the correct answer.


⭐ Closing

Nice work! This key topic is really all about combining what you’re learned so far about limits. On the AP, they’ll likely ask you to do this more than practicing the skills individually.