<< Hide Menu

📚

 > 

♾️ 

 > 

🤓

2.1 Defining Average and Instantaneous Rates of Change at a Point

2 min readjune 18, 2024

Welcome back to AP Calculus with Fiveable! After covering Limits and Continuity in Unit 1, we are now diving into Unit 2: Differentiation - Definition and Basic Derivative Rules. Our focus in this section is to understand the concepts of average and instantaneous rates of change at a point. Let’s get into it! ⬇️


✈️ Average Rate of Change

In real-world scenarios, the average rate of change is often used to represent average speed, average velocity, or average growth rate. In calculus, understanding rates of change is crucial, which is much like the concept of slope in algebra.

Untitled

Image courtesy of Rebecca

For any two points on a continuous function f(x)f(x) within the interval [a,b][a,b], the average rate of change can be expressed as:

f(b)f(a)ba\frac{f(b) - f(a)}{b - a}

This is also the slope of the secant line between any two points.


⛷️ Instantaneous Rate of Change

While the average rate of change informs us how a function behaves over an interval [a,b][a,b], the instantaneous rate of change tells us the rate of change at an exact point. In calculus, we express this using the derivative.

The instantaneous rate of change of a function f(x)f(x) at a specific point x=cx=c is denoted as f(x)f'(x) and is given by the limit:

f(c)=limh0f(c+h)f(c)hf'(c) = \lim_{h \to 0} \frac{f(c + h) - f(c)}{h}

This limit represents the slope of the tangent line to the graph of f(x)f(x) at the point (c,f(c))(c, f(c) ). In other words, it tells us how fast the function is changing precisely at the point x=cx=c.


🏋️‍♂️**** Practice Problems

Let’s work on a few questions to get the concepts down! Here are a few steps you can follow when approaching problems that ask you to solve for average rate of change or instantaneous rate of change:

  1. 👀 Identify the function and the interval.
  2. ✏️ Apply the formula for the rate of change you are solving for, either average or instantaneous.
  3. ✅ Substitute the values and solve.

1) Solving Average Rate of Change

Consider the function f(x)=x2f(x) = x^2 over the interval [1,3][1,3]. Calculate the average rate of change.

👉 Step 1: Identify the function and the interval.

f(x)=x2f(x) = x^2

[a,b]=[1,3][a,b] = [1,3]

👉 Step 2: Apply the formula for an average rate of change.

Average rate of change =f(3)f(1)31= \frac{f(3) - f(1)}{3 - 1}

👉 Step 3: Substitute the values and solve.

Average rate of change =32122=912=4=\frac{3^2 - 1^2}{2} =\frac{9 - 1}{2}=4

2) Solving Instantaneous Rate of Change

Consider the function f(x)=x2f(x) = x^2. Find the instantaneous rate of change at x=2x=2.

👉 Step 1: Identify the function and the point.

f(x)=x2f(x) = x^2

c=2c = 2

👉 Step 2: Apply the formula for the instantaneous rate of change.

Instantaneous rate of change:

f(2)=limh0f(2+h)f(2)hf'(2) = \lim_{h \to 0} \frac{f(2 + h) - f(2)}{h}

👉 Step 3: Substitute the values and solve.

Instantaneous rate of change:

limh0(2+h)222h=limh0h2+4h+44h=limh0h(h+4)h=limh0h+4=4\lim_{h \to 0} \frac{(2 + h)^2 - 2^2}{h} =\lim_{h \to 0} \frac{h^2 + 4h + 4-4}{h} =\lim_{h \to 0} \frac{h(h + 4)}{h} =\lim_{h \to 0} {h+4}=4

😌 Summing it Up

You made it to the end of the first topic in unit 2! Great work. Here’s a quick table displaying the differences between average and instantaneous rates of change for you to take with you throughout the unit.

AspectAverage Rate of ChangeInstantaneous Rate of Change
Time SpanOver an interval of valuesAt a specific instant
MeasurementRepresents an average behaviorRepresents the exact rate at one point on a function curve
CalculationUses a slope formula between two points on a function curveUtilizes the derivative formula for a specific point
PrecisionGives an approximationProvides an exact value
PurposeUseful for understanding overall trends or changesHelpful for determining precise moments of change

Best of luck! 🍀