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2.8 The Product Rule

3 min readjune 18, 2024

2.8 The Product Rule

Welcome back to AP Calculus with Fiveable! This topic focuses on taking the derivative of a product. We’ve worked through derivatives at a point, sum and difference rules, and trigonometric derivatives, so let's keep building our derivative skills. 🙌

🏁 Product Rule Definition

To find the derivative of a product of functions, we need to multiply the first function by the derivative of the second and add it to the second function multiplied by the derivative of the first.

ddx(f(x)g(x))=f(x)g(x)+g(x)f(x)\frac{d}{dx}(\textcolor{red}{f(x)}\textcolor{green}{g(x)})= \textcolor{red}{f(x)} \textcolor{blue}{g'(x)} + \textcolor{green}{g(x)} \textcolor{pink}{f'(x)}

A fun way to remember this rule is by saying:

“First d second (first function times the derivative of the second)

Plus second d first (second function times the derivative of the first).” 😁

This is necessary because the product of derivatives of two functions does not equal the derivative of a product of two functions.

✏️ Product Rule: Walkthrough

For example, let’s find the derivative of the following function:

f(x)=sin(x)(x2+2x)f(x) = \sin(x)(x^2 + 2x)

Using the product rule, we can find that:

f(x)=sin(x)ddx(x2+2x)+(x2+2x)ddx(sin(x))\textcolor{green}{f'(x)} = \sin(x)*\frac {d}{dx}(x^2 + 2x) + (x^2+2x)*\frac {d}{dx}(\sin(x))
f(x)=sin(x)(2x+2)+(x2+2x)cos(x)\textcolor{green}{f'(x)} = \sin(x)(2x+2) + (x^2+2x)\cos(x)

If we incorrectly attempt to calculate the derivative of f(x)f(x), it would say

f(x)=cos(x)(2x+2)\textcolor{red}{f'(x)} = cos(x)( 2x + 2)

However, sin(x)(2x+2)+(x2+2x)cos(x)cos(x)(2x+2)\textcolor{green}{sin(x)(2x+2) + (x^2+2x)cos(x)} \neq \textcolor{red}{cos(x)( 2x + 2)}.

This can be seen in the following graphs. f(x)f'(x) represents the correct derivative of f(x)f(x) because the critical points and positive and negative values match the original functions.

Screen Shot 2023-12-12 at 1.58.12 PM.png

Graph of f(x)f(x) created with Desmos

Screen Shot 2023-12-12 at 1.35.31 PM.png

Graph of f(x)f'(x) created with Desmos

Screen Shot 2023-12-12 at 1.58.24 PM.png

Incorrect Graph of f(x)f'(x); Graph created with Desmos


🧮 Product Rule: Practice Problems

Let’s work on a few questions and make sure we have the concept down!

Product Rule: Example 1

Find yy' for y=(3x24x)(2x1)y = (3x^2-4x)(2x-1) with and without the Product Rule.

Solving Example 1 Without Product Rule

To find yy' without the product rule, we have to first expand the function.

y=6x33x28x2+4xy = 6x^3 - 3x^2- 8x^2 + 4x
y=6x311x2+4xy = 6x^3 -11x^2 + 4x

Now we can take the derivative, using the derivative sum rule. Therefore,

y=18x222x+4y' = 18x^2 - 22x + 4

Solving Example 1 With Product Rule

We can quickly use the product rule to solve for yy'.

y=(3x24x)ddx(2x1)+(2x1)ddx(3x24x)y' = (3x^2-4x)* \frac{d}{dx}(2x-1) + (2x-1)* \frac{d}{dx}(3x^2-4x)

Therefore,

y=(3x24x)(2)+(2x1)(6x4)y' = (3x^2-4x)(2) + (2x-1)(6x-4)

Unless specified, you do not have to simplify for the AP Calculus Exam, so this answer is perfectly acceptable! ✅

Product Rule: Example 2

Find f(x)f'(x) if f(x)=sin(x)(3x22x+5)f(x) = \sin(x)(3x^2 - 2x + 5).

Let's use the product rule to find the derivative of f(x)f(x). Don’t forget, the derivative of sin(x)\sin(x) is cos(x)\cos(x)! Brush up on your trig derivatives with this Fiveable guide: Derivatives of cos x, sinx, e^x, and ln x.

f(x)=sin(x)ddx(3x22x+5)+(3x22x+5)ddxsin(x)f'(x) = \sin(x)*\frac{d}{dx}(3x^2-2x+5) + (3x^2-2x+5)*\frac{d}{dx}\sin(x)

Therefore,

f(x)=sin(x)(6x2)+(3x22x+5)cos(x)f'(x) = \sin(x)(6x-2) + (3x^2-2x+5)\cos(x)

Product Rule: Example 3

Find yy' if y=exsin(x)y = e^x\sin(x)

Remember that the derivative of exe^x is still exe^x! Now we can use the product rule.

y=exddx(sin(x))+sin(x)ddx(ex)y'=e^x * \frac{d}{dx}(\sin(x)) + \sin(x)*\frac{d}{dx}(e^x)

Therefore,

y=excos(x)+exsin(x)y' = e^x\cos(x) + e^x\sin(x)

🌟 Closing

Great work! 🙌 The product rule is a key foundational topic for AP Calculus. You can anticipate encountering questions involving the product rule on the exam, both in multiple-choice and as part of a free response.

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Image Courtesy of Giphy